Subject
Quantitative Aptitude
Topic
Number
The dimensions of a room are 15.17 m and 9.02 m. The floor of the room is to be paved with square tiles of uniform size. Determine the length of the largest possible size of the tile.
The dimensions of a room are 15.17 m and 9.02 m. The floor of the room is to be paved with square tiles of uniform size. Determine the length of the largest possible size of the tile.
ক)
0.18 mখ)
0.41 mগ)
0.5 mঘ)
0.92 mঙ)
1.20 mExplanation
Here, Length of the room = 15.17 m = 1517 cm Breadth of the room = 9.02 m = 902 cm Now, the floor is to be paved with equal sized square tiles. To find the size largest possible tile with which the floor can be paved, we have to find the HCF of 1517 and 902. ∴ Length of largest tile = (H.C.F. of 1517 and 902) 1517 = 37 × 41 902 = 2 × 11 × 41 ∴ HCF of 1517 and 902 = 41 ∴ Length of largest tile = 41 cm = 0.41 mRelated questions
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