Subject

    Quantitative Aptitude

    Topic

    Average

    The average weight of 3 men A, B and C is 96kg. Another man D joins the group and the average now becomes now 88 kg. if another man E, whose weight is 4 kg more than that of D, replace A, then the average weight B, C, D and E becomes 82 kg. The weight of A is:

    ক)
    70 kg
    খ)
    72 kg
    গ)
    92 kg
    ঘ)
    80 kg
    ঙ)
    None of these

    Explanation

    Let the weights of A, B, C, D, E be a, b, c, d, e kgs respectively. We know that, Average = (Sum of all terms)/(Number of terms) ∴ Sum of all terms = Average × number of terms ∵ Average of a, b, c is 96, a + b + c = 3 × 96 = 288 ∵ Average of a, b, c, d is 88, a + b + c + d = 4 × 88 = 352 ∴ d = 352 - 288 = 64 ∵e is 4 more than d, e = 64+ 4 = 68 Now, since the average of b, c, d, e is 82, b + c + d + e = 4 × 82 = 328 ∴b + c = 328 - d - e = 328 - 64 – 68 ⇒ b + c = 196 a = (a + b + c) - (b + c) = 288 - 196 = 92 Weight of A = 92 Kg

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