Subject
Quantitative Aptitude
Topic
Miscellaneous
The amount of alcohol in two varieties of whiskey are 27% volume/volume and 42% volume/volume. In what ratio should they be mixed so that the mixture has 33% volume/volume alcohol?
The amount of alcohol in two varieties of whiskey are 27% volume/volume and 42% volume/volume. In what ratio should they be mixed so that the mixture has 33% volume/volume alcohol?
ক)
8 : 7খ)
3 : 2গ)
2 : 1ঘ)
1 : 1Explanation
Let the whiskeys are mixed in amounts M litres and N litres. ⇒ Amount of alcohol in first variety = 0.27M ⇒ Amount of alcohol in second variety = 0.42N Total amount of mixture = (M + N) litres Amount of alcohol in mixture = 33% volume/volume = 0.33(M + N) ⇒ 0.27M + 0.42N = 0.33(M + N) ⇒ 0.09N = 0.06M ⇒ M/N = 3/2 ∴ Ratio in which they should be mixed is 3 : 2.Related questions
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