Subject

    Quantitative Aptitude

    Topic

    Simplification

    Simplify:[(21664)23  ×(25681)−14÷(16144)−12]12{\left[ {{{\left( {\frac{{216}}{{64}}} \right)}^{\frac{2}{3}\;}} \times {{\left( {\frac{{256}}{{81}}} \right)}^{ - \frac{1}{4}}} \div {{\left( {\frac{{16}}{{144}}} \right)}^{ - \frac{1}{2}}}} \right]^{\frac{1}{2}}}

    ক)
    3/4
    খ)
    2/5
    গ)
    1/4
    ঘ)
    1/5
    ঙ)
    None of these

    Explanation

    Laws of indices: (a m ) n = a m × n a m × a n = a m+n a m ÷ a n = a m [(21664)2/3  ×(25681)−1/4÷(16144)−1/2]1/2{\left[ {{{\left( {\frac{{216}}{{64}}} \right)}^{2/3\;}} \times {{\left( {\frac{{256}}{{81}}} \right)}^{ - 1/4}} \div {{\left( {\frac{{16}}{{144}}} \right)}^{ - 1/2}}} \right]^{1/2}} = {\left[ {{{\left( {\frac{{216}}{{64}}} \right)}^{2/3\;}} \times {{\left( {\frac{{81}}{{256}}} \right)}^{1/4}} \times {{\left( {\frac{{16}}{{144}}} \right)}^{1/2}}} \right]^{1/2}}^\; = {\left[ {\frac{{36}}{{16}} \times \frac{3}{4} \times \frac{4}{{12}}} \right]^{1/2}}{\;^\;} = {\left( {\frac{9}{{16}}} \right)^{\frac{1}{2}}}^\; = (3/4)

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