Subject
Bank Exam
Topic
IFIC Bank Ltd. MTO 2013
Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?
Set X contains 10 consecutive integers. If the sum of the 5 smallest members of set X is 265, what is the average of the 5 largest members of Set X?
ক)
58খ)
59গ)
60ঘ)
57Explanation
x+x+x+x+x+1+2+3+4+5 = 265 or, 5x + 15 = 265 or, 5x = 265 - 15 = 250 or, x = 50 The largest 5 member of the set is, 50+6 = 56 50+7 =57 50+8 = 58 50+9= 59 50+10= 60 Then, Average = (56+57+58+59+60) / 5 = 290/5 = 58Related questions
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