Subject

    Quantitative Aptitude

    Topic

    Speed & Distance

    Rajan is travelling at a speed of 24 km/h reaches a particular place 10 minutes early but when he travels at a speed of 16 km/h he reaches the same place from the same point 10 minutes late. Find the distance.

    ক)
    11 km
    খ)
    15 km
    গ)
    12 km
    ঘ)
    16 km
    ঙ)
    None of these

    Explanation

    We know that formulae: → Speed = Distance/Time → When someone reaches destination ‘a’ hours before than usual time, walking with speed ‘u’ and he reaches destination ‘b’ hours later than usual time, walking with speed ‘v’, then – Travelled distance = u×vu∼v×(a+b)\frac{{u \times v}}{{u \sim v}} \times \left( {a + b} \right) {Where ‘u’ and ‘v’ are faster and slower speeds in km/h respectively} ∴ Required distance =24×1624−16×(1060+1060)=48×13=16  km= \frac{{24 \times 16}}{{24 - 16}} \times \left( {\frac{{10}}{{60}} + \frac{{10}}{{60}}} \right) = \frac{{48 \times 1}}{3} = 16\;km Hence, the required distance is 16 km.

    Find Tutors

    View all Tutors