Subject

    Quantitative Aptitude

    Topic

    Speed & Distance

    Prakash runs 2 km in 4 min and Shikha in 4 min 10 sec. How many meters start must Prakash give Shikha so that the race may end in a dead heat?

    ক)
    80 m
    খ)
    72 m
    গ)
    85 m
    ঘ)
    77 m
    ঙ)
    89 m

    Explanation

    Speed = distance/time Time taken by Prakash to run 2000m = 4 min = 4 × 60 = 240 sec ∴ Speed of Prakash, x = 2000/240 m/s Time taken by Shikha to run 2000m = 4min 10sec = 4 × 60 + 10 = 250 sec ∴Speed of Shikha, y = 2000/250 m/s To meet dead heat, both of them must complete the race in equal time, i.e. 240 sec Difference in speeds = x – y = 2000240−2000250=13m/sec\frac{{2000}}{{240}} - \frac{{2000}}{{250}} = \frac{1}{3}m/sec Total distance by which Shikha should be ahead of Prakash at the beginning of the race =13×240=80m= \frac{1}{3} \times 240 = 80m

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