Subject
Quantitative Aptitude
Topic
Permutation & Combination
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
ক)
210খ)
1050গ)
25200ঘ)
21400Explanation
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C3x 4C2) = {(7 x 6 x 5)/( 3 x 2 x 1)} x {(4 x 3)/( 2 x 1)} = 210. Number of groups, each having 3 consonants and 2 vowels = 210. Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 5 x 4 x 3 x 2 x 1 = 120. So, Required number of ways = (210 x 120) = 25200.Related questions
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