Subject
Quantitative Aptitude
Topic
Number
On dividing 2272 as well as 875 by 3-digit number N,we get the same remainder.The sum of the digits of N is:
On dividing 2272 as well as 875 by 3-digit number N,we get the same remainder.The sum of the digits of N is:
ক)
13খ)
12গ)
11ঘ)
10Explanation
(2272-875) = 1397, is exactly divisible by N. Now , 1397 = 11 x 127 The required 3-digit number is 127,the sum of digits is 10.Related questions
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