Subject
Quantitative Aptitude
Topic
Time and Work
Max’s efficiency is 2/5th Kendrick’s efficiency. Max starts off three pieces of work and works for a day alone and Kendrick joins him for the next half a day. As Max leaves after that, Kendrick bucks up and doubles his efficiency. If he can finish the remaining work alone in 4 hours, then in how much time could Max and Kendrick together do one piece of work at initial efficiency?
Max’s efficiency is 2/5th Kendrick’s efficiency. Max starts off three pieces of work and works for a day alone and Kendrick joins him for the next half a day. As Max leaves after that, Kendrick bucks up and doubles his efficiency. If he can finish the remaining work alone in 4 hours, then in how much time could Max and Kendrick together do one piece of work at initial efficiency?
ক)
\(3\frac{1}{{25}}\) daysখ)
1 daysগ)
\(1\frac{5}{{12}}\) hoursঘ)
5 daysঙ)
None of theseExplanation
Let Kendrick be able to complete one piece of work in x days. ⇒ In one day, work done by Kendrick alone = 1/x ---(1) ∴ Work done by Max in 1 day = (2/5x) ---(2) (given) Work done by Max and Kendrick in 1 day = (1/x) + (2/5x) = 7/5x ---(3) ∴ Work done by Max and Kendrick in half a day = 7/10x ---(4) From 2 and 4, Total work completed at the end of 1.5 days = (2/5x) + (7/10x) = 11/10x ∴ Remaining work =3- (11/10x) = (30x – 11)/ 10x If Kendrick doubles his efficiency in a day, Work done by Kendrick in 1 day = 2/x If it takes 4 hours (i.e. 1/6th of a day) for him to finish remaining work, (1/6) × (2/x) = (30x – 11)/ 10x ⇒ x = 43/90 ∴ Work done by Kendrick and Max together in 1 day = 7/5x = (7 × 90)/(5 × 43) = 126/43 ∴ if it takes n days for them to finish a single piece of work together,Related questions
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