Subject

    Quantitative Aptitude

    Topic

    Miscellaneous

    In the mixture of 60 L the ratio of acid and water is 2 : 1 respectively. If the ratio of acid and water is to be 1 : 2, then the amount of water (in liters) to be added to the mixture is

    ক)
    75 L
    খ)
    60 L
    গ)
    50 L
    ঘ)
    45 L
    ঙ)
    None of these

    Explanation

    Total quantity of the mixture = 60 L ∴ Quantity of acid in the mixture = 2/3 × 60 = 40 L ∴ Quantity of water in the mixture = 1/3 × 60 = 20 L Let required quantity of water be x L. According to the question, 4020+x=12⇒80=20+x\frac{{40}}{{20 + x}} = \frac{1}{2} \Rightarrow 80 = 20 + x ⇒ x = 60 L Hence, the required quantity of the water to be added to the mixture is 60 L

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