Subject

    Quantitative Aptitude

    Topic

    Triangle

    In the figure right, if CP = BP and x° = 120°, then y = ?

    ক)
    30°
    খ)
    45°
    গ)
    60°
    ঘ)
    75°

    Explanation

    x° = 120°  CP=BP ∠ BCP=60°=∠ CBP y+∠ BCP+∠ CBP=180° y=60°

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