Subject
Bank Exam
Topic
Joint Recruitment Test for 2 Banks (Officer)IT/ICT [04-01-2019, AUST]
In an acute triangle ABC, if sin2(A+B-C) = 1 and tan(B+C-A)=√3, than the value of angleB is
In an acute triangle ABC, if sin2(A+B-C) = 1 and tan(B+C-A)=√3, than the value of angleB is
ক)
300খ)
52Λ1/2গ)
600ঘ)
450Explanation
দেয়া আছে, sin2(A+B-C) = 1 => sin2(A+B-C) = sin90 0 [ ∴sin90 0 = 1 ] => 2(A+B-C) = 90 0 A+B-C = 45 0 ...............(i) আবার, tan(B+C-A)=√3 => tan(B+C-A)= tan60 0 [ ∴tan60 0 = √3 ] => B+C-A= 60 0 ...........(ii) এখন, (i) এবং (ii) নং সমীকরণ যোগ করে পাই A+B-C = 45 0 B+C-A= 60 0 2B = 105 0 B = 105 0 /2 = 52 Λ1/2Related questions
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