Subject

    Quantitative Aptitude

    Topic

    Probability

    In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear

    ক)
    7/15
    খ)
    5/18
    গ)
    13/18
    ঘ)
    3/16

    Explanation

    n(S) = 36 A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)} B = { (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) } n(A)=6,  n(B)=5,  n(A∩B)=1n\left(A\right)=6,\;n\left(B\right)=5,\;n\left(A\cap B\right)=1 ∴ Required probability = P(A∪B)P\left(A\cup B\right) = P(A)+P(B)−P(A∩B)P\left(A\right)+P\left(B\right)-P\left(A\cap B\right) = 636+536−136\frac6{36}+\frac5{36}-\frac1{36} = 518\frac5{18}

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