Subject

    Quantitative Aptitude

    Topic

    Permutation & Combination

    In a simultaneous throw of two dice, what is the probability of getting a total of 7?

    ক)
    1/2
    খ)
    1/3
    গ)
    1/4
    ঘ)
    1/6
    ঙ)
    None of these

    Explanation

    In a simultaneous throw of two dice – Number of possible outcomes n(s) = 6 × 6 = 36 Number of favourable events = n(E) = {(1, 6); (2, 5), (3, 4), (4, 3), (5, 2), (6,1)} ⇒ n(E) = 6 ∴ Required probability of getting a total of 7 – P(E)=n(E)n(S)P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} =636=16= \frac{6}{{36}} = \frac{1}{6}

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