Subject
Quantitative Aptitude
Topic
Mensuration
In a right circular cylinder, 4 times the sum of the areas of its two circular faces is twice the area of its curved surface. The height of a right circular cylinder is 6 m. Then the radius of the base is:
In a right circular cylinder, 4 times the sum of the areas of its two circular faces is twice the area of its curved surface. The height of a right circular cylinder is 6 m. Then the radius of the base is:
ক)
3 mখ)
2 mগ)
6 mঘ)
1.5 mঙ)
3.5 mExplanation
Given that, 4 times the sum of the areas of two circular faces is twice the area of its curved surface. The height of a right circular cylinder is 6 m. we know that, Area of curved surface of the cylinder = 2 π r h Area of right circular face = π r 2 Then, 4 × Sum of the areas of its two circular faces = 2 × Area of curved surface of the cylinder ⇒ 4 × (π r 2 + π r 2 ) = 2 ×2 π r h ⇒ 8 π r 2 = 4 π r h ⇒ 2 r = h Or, r = h/2 = 6/2 = 3 m.Related questions
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