Subject

    Quantitative Aptitude

    Topic

    Probability

    In a race, the odd favour of cars P,Q,R,S are 1:3, 1:4, 1:5 and 1:6 respectively. Find the probability that one of them wins the race.

    ক)
    319/420
    খ)
    27/111
    গ)
    114/121
    ঘ)
    231/420

    Explanation

    P(P)=14,P(Q)=15,P(R)=16,P(S)=17P(P)=\frac14,P(Q)=\frac15,P(R)=\frac16,P(S)=\frac17 All the events are mutually exclusive hence, Required probability = P(P)+P(Q)+P(R)+P(S) = 14+15+16+17\frac14+\frac15+\frac16+\frac17 = 319420\frac{319}{420}

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