Subject

    Quantitative Aptitude

    Topic

    Percentage

    In a medical certificate, by mistake a candidate gave his height as 23% more than normal. In the interview panel, he clarified that his height was 5 feet 7 inches. Find the percentage correction made by the candidate from his stated height to his actual height.

    ক)
    23%
    খ)
    18.7%
    গ)
    25%
    ঘ)
    15%
    ঙ)
    None of the above

    Explanation

    Actual height of the candidate = 5 feet 7 inches ∴ Actual height of the candidate = (5 × 12 ) + 7 inches ∴ Actual height of the candidate = 67 inches Height mentioned by the candidate = 67 + (23 % of 67 ) ∴Height mentioned by the candidate = 82.41 inches % correction from stated to actual height = Stated  height−actual  height  stated  height    ×100\frac{{Stated\;height - actual\;height\;}}{{stated\;height\;}}\; \times 100 ∴ % correction = 82.41−6782.41×100\frac{{82.41 - 67}}{{82.41}} \times 100 ∴ % correction = 18.7 Thus % correction made from stated to actual height is 18.7 %

    Find Tutors

    View all Tutors