Subject
Quantitative Aptitude
Topic
Probability
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
ক)
1/3খ)
3/4গ)
7/19ঘ)
8/21Explanation
Total number of balls = (8 + 7 + 6) = 21. Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue. So, n(E) = 7. Therefore, P(E) = n(E)/ n(S) = 7/21 = 1/3Related questions
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