Subject
Quantitative Aptitude
Topic
Speed & Distance
In a 500 m race, the ratio of speeds of two contestants P and Q is 3 : 4. P has a head start of 146 m. Then, P wins by
In a 500 m race, the ratio of speeds of two contestants P and Q is 3 : 4. P has a head start of 146 m. Then, P wins by
ক)
60 mখ)
40 mগ)
20 mঘ)
10 mঙ)
28 mExplanation
P has a headstart of 146 m. ∴ the distace to be travelled by P = 500 – 145 = 354 m Both run for the same time during the race. Distance = speed × time ∵ Ratio of speeds of P : Q = 3 : 4 In equal time, the distance travelled by them will also be in the ratio of their speeds, i.e. 3 : 4. P needs to travel only 354 m to win the race. Distance travelled by Q in the time P travels 354 metres ∴ By the time P finishes the race (i.e. the 500 m mark), Q has covered 472 m. Hence P beats Q by (500 – 472 =) 28 mRelated questions
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