If x = (√3 + 1)/ (√3-1) and y = (√3 – 1)/… | Answer

Subject

Quantitative Aptitude

Topic

Power & Logarithm

If x = (√3 + 1)/ (√3-1) and y = (√3 – 1)/(√3+1), then the value of (x2+ y2) is:
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Explanation

x = (√3 + 1)/( √3-1) x (√3 + 1)/ (√3+1) => x = ((√3 + 1)2)/(3-1) =>x = (3 + 1 + 2√3)/2 = 2 + √3. y =(√3 - 1) / (√3+1) x (√3 - 1)/( √3-1) => y = (√3 - 1)2/(3-1) => y = 3 + 1 - 2√3 = 2 - √3. So, x2 + y2 = (2 + √3)2 + (2 - √3)2 = 2(4 + 3) = 14

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If x = (√3 + 1)/ (√3-1) and y = (√3 – 1)/(√3+1), then the value of (x2+ y2) is:Reading

If x = (√3 + 1)/ (√3-1) and y = (√3 – 1)/(√3+1), then the value of (x2+ y2) is:

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If x = (√3 + 1)/ (√3-1) and y = (√3 – 1)/(√3+1), then the value of (x2+ y2) is:
Reading