Subject
Quantitative Aptitude
Topic
Mensuration
If two opposite sides of a square are increased by 10 cm each, then the sides of previous and new figure are in the ratio of 11:12. What is the area of the original square?
If two opposite sides of a square are increased by 10 cm each, then the sides of previous and new figure are in the ratio of 11:12. What is the area of the original square?
ক)
11000 cm2খ)
12100 cm2গ)
22010 cm2ঘ)
44100 cm2ঙ)
None of theseExplanation
Let the original side of the square be X cm, then new sides of the new figure would be X cm and X+10 cm. Now, new ratio of the sides = X : X + 10, ⇒ 11 : 12 = X : X + 10, Solving, X = 110 cm. ∴ Side of the original square = 110 cm. ∴ Area of the original square = multiplication of both sides = 110 × 110 = 12100 cm 2 .Related questions
The adjacent sides of a parallelogram are 12cm and 14cm and angle between them is 60°. What is the area of the parallelogram?One of the diagonal of a rhombus is 60% of other diagonal. How many times the square of the length of the other diagonal equals the area of the rhombs?The area of trapezium, whose parallel sides are 3.0 m and 6.0 m and perpendicular distance between them is 8.0 m, is:If area of a rhombus is 225 cm2. One of the diagonal is half of the other diagonal. The sum of the diagonals would be:The perimeter of a square is one-fourth of the perimeter of a Rectangle. If the perimeter of the square is 44 cm, and the length of the Rectangle is 51 cm, what is the difference between the breadth of the Rectangle and the side of the square?Find the area of a parallelogram with base is 5 cm and altitude is 4.2 cm.Diagonals of a rhombus are 16 m and 12 m respectively. Find the area of the rhombus.What will be the length of the diagonal of that square plot whose area is equal to the area of a rectangular plot of length 64 m and breadth 49 m?
