Subject
Quantitative Aptitude
Topic
Number
If the number 97215k6 is completely divisible by 11, then the smallest whole number in place of ‘K’ would be:
If the number 97215k6 is completely divisible by 11, then the smallest whole number in place of ‘K’ would be:
ক)
2খ)
3গ)
5ঘ)
0ঙ)
None of theseExplanation
We know that: A number is divisible by 11 if difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a number divisible by 11. Given number = 97215k6 So, (6+5+2+9) - (k + 1 + 7) = (14 - k), which must be divisible by 11 ∴ K = 3Related questions
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