Subject
Bank Exam
Topic
Southeast Bank Ltd. 2011 (PO)
If the average (arithmetic mean) of a, b, and c is 40, what is the average (arithmetic mean) of (3a + 10), (3b +10), and (3c+10)?
If the average (arithmetic mean) of a, b, and c is 40, what is the average (arithmetic mean) of (3a + 10), (3b +10), and (3c+10)?
ক)
90খ)
120গ)
130ঘ)
150Explanation
(a + b + c) / 3 = 40 or, a + b + c = 120 or, 3 * (a + b + c) = 120 * 3 or, 3a + 3b + 3c = 360 or, 3a + 3b + 3c + 30 = 360 + 30 or, (3a + 10) + (3b + 10) + (3c + 10) = 390 or, [(3a + 10) + (3b + 10) + (3c + 10)] / 3 = 390/3 = 130Related questions
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