Subject

    Quantitative Aptitude

    Topic

    Number

    If n is natural number , then (6n2+6n)\left(6n^2+6n\right) is always divisible by :

    ক)
    6 only
    খ)
    6 and 12 both
    গ)
    12 only
    ঘ)
    by 18 only

    Explanation

    (6n2+6n)=6n(n+1)\left(6n^2+6n\right)=6n\left(n+1\right) , which is always divisible by 6 and 12 both, since n(n+1) is always even.

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