Subject
Quantitative Aptitude
Topic
Number
If n is a natural number, then (6n2+ 6n) is always divisible by:
If n is a natural number, then (6n2+ 6n) is always divisible by:
ক)
6 onlyখ)
6 and 12 bothগ)
12 onlyঘ)
by 18 onlyExplanation
(6n2 + 6n) = 6n(n + 1), Which is always divisible by 6 and 12 both, since n(n + 1) is always even.Related questions
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