Subject
Bank Exam
Topic
Joint Recruitment Test for 7 Banks and Financial Institutions - (Senior Officers) - 05.11.2021
If cot (x – 30°) = 1/√3, sin x = ?
If cot (x – 30°) = 1/√3, sin x = ?
ক)
1/2গ)
1ঘ)
√3/2Explanation
cot (x-30º) = 1/√3 = cot 60º ⇒ x-30º= 60º [As we know, cot 60º = 1/√3] ⇒ x = 90º Now, sinx = sin90º = 1Related questions
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