Subject

    গাণিতিক যুক্তি

    Topic

    অসমতা

    If b < 2 and 2x - 3b = 0, which of the following must be true ?

    ক)
    x > -3
    খ)
    x < 2
    গ)
    x = 3
    ঘ)
    x < 3

    Explanation

    Given the equation 2x−3b=02x - 3b = 0, we first solve for xx in terms of bb: 2x=3b2x = 3b, so x=32bx = \frac{3}{2}b. Since we are given the condition b<2b < 2, we multiply both sides by 32\frac{3}{2} (a positive number) to maintain the inequality direction: 32b<32(2)\frac{3}{2}b < \frac{3}{2}(2), which simplifies to x<3x < 3. Elimination: A ('x > -3') is incorrect because bb can be negative (e.g., if b=−4b=-4, x=−6x=-6, which is not greater than -3). B ('x < 2') is incorrect because if bb approaches 2 (e.g., b=1.9b=1.9), xx approaches 2.852.85, which is greater than 2. C ('x = 3') is incorrect because xx must be strictly less than 3, as bb is strictly less than 2.

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