Subject

    Quantitative Aptitude

    Topic

    Ratio

    If a + b = P, a – b = Q, c + d = R and c - d = S & ab=cd\frac{a}{b} = \frac{c}{d} t1QsGL7iAz1qmcJmEB9nR1KyiAUnyxS1LAL

    ক)
    \(P = \frac{{QR}}{S}\)
    খ)
    \(Q = \frac{{PS}}{R}\)
    গ)
    \(R = \frac{{PS}}{Q}\)
    ঘ)
    \(S = \frac{{QR}}{P}\)
    ঙ)
    All of the above

    Explanation

    Given: a + b = P, a – b = Q, c + d = R and c - d = S ---- (1) a/b=c/d Apply componendo & dividendo, (a+b)/(a-b)=(c+d)/(c-d) P/Q=R/S  (using statement (1)) ⇒ P=QR/S , Q=PS/R  , R=PS/Q  and S=QR/P.

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