Subject
Quantitative Aptitude
Topic
Number
If 5x2 – 13 xy + 6y2 = 0, then x : y is:
If 5x2 – 13 xy + 6y2 = 0, then x : y is:
ক)
(2 : 1) onlyখ)
(3 : 5) onlyগ)
(5 : 3) or (1 : 2)ঘ)
(3 : 5) or (2 : 1)ঙ)
(5 : 3) or (2 : 1)Explanation
5x2 – 13 xy + 6y2 = 0 ⇒ 5x2 – 10xy – 3xy + 6y2 = 0 ⇒ 5x (x – 2y) – 3y(x – 2y) = 0 ⇒ (x – 2y)(5x – 3y) = 0 ⇒ x = 2y or 5x = 3y ⇒ x/y = 2/1 or 3/5Related questions
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