Subject
Quantitative Aptitude
Topic
Number
If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?
If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ?
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1Explanation
Let assume the value of a,b &c that will satisfy the equation. so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1 here all three cases satisfy the equation assume any one a=1,b=1,c= -1 Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0Related questions
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