Subject
Quantitative Aptitude
Topic
Number
How many 3-digit numbers can be formed the digits 2, 3, 4, 5, 6,7 and 9, which are divisible by 5 and none of the digits is repeated?
How many 3-digit numbers can be formed the digits 2, 3, 4, 5, 6,7 and 9, which are divisible by 5 and none of the digits is repeated?
ক)
5খ)
10গ)
15ঘ)
20Explanation
As the 3 digit number must be a multiple of 5, it must have 5 in its units place Ex: xy5. X and Y can be any of the remaining 5 digits(2,3,6,7,9). These remaining 5 digits can have 5p2 permutations ( P- because the arrangement is important). 5p2 =20. That gives 20 possible arrangements of the 5 digits.Related questions
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:A number is as much greater than 36 as the less than Find the number.If one-third of one-fourth of a number is 15, then three-tenth of that number is:If the number 5 * 2 is divisible by 6, then * =?কাজের দিন ২ টাকা পাওনা এবং অনুপস্থিতির দিন ৫০ পয়সা জরিমানা এই শর্তে সেপ্টেম্বর মাসে ৪০ টাকা পেল। সে কত দিন কাজে উপস্থিত ছিল?476 ** 0 is divisible by both 3 and The non-zero digits in the hundred's and ten's places are respectively:The sum of two numbers is 25 and their difference is Find their product.