Correct answer: Option 1 (2 and 3). Explanation (textbook style, using Vieta and factoring): For the quadratic x2−5x+6=0 (here a=1,b=−5,c=6), Vieta's formulas state that if the roots are r1,r2 then r1+r2=−ab and r1r2=ac. Thus r1+r2=−1−5=5 and r1r2=16=6. We need two numbers whose sum is 5 and product is 6; these numbers are 2 and 3. Therefore the roots are 2 and 3. Equivalently, factor the quadratic: x2−5x+6=(x−2)(x−3). Setting this to zero gives (x−2)(x−3)=0, so x=2 or x=3.