Subject
Quantitative Aptitude
Topic
Speed & Distance
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point P from the foot of the tower is:
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point P from the foot of the tower is:
ক)
149 mখ)
156 mগ)
173 mঘ)
200 mExplanation
Let, AB be the tower. Then, ÐAPB = 300 and AB = 100 m. AB/AP = tan 300 = 1/√3 => AP = (AB × √3) m = 100√3 m = (100 × 1.73) m = 173 m.Related questions
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