Subject

    Quantitative Aptitude

    Topic

    Miscellaneous

    From a container of wine a man stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus in three attempts the ratio of water and wine becomes 169 : 343. The initial amount of wine in the container was:

    ক)
    130 litres
    খ)
    140 litres
    গ)
    120 litres
    ঘ)
    90 litres
    ঙ)
    None of these

    Explanation

    Let the initial amount of wine in the container was k, then according to the question, wine leftwater added=343169\frac{{wine\ left}}{{water\ added}} = \frac{{343}}{{169}} It means – wine leftwater(initial amount)=343512\frac{{wine\ left}}{{water\left( {initial\ amount} \right)}} = \frac{{343}}{{512}} (because 343 + 169 = 512) Thus, 343x=512x(1−15k)3⇒343512=(78)3=(1−15k)3⇒(1−15k)=78=(1−18)\begin{array}{l} 343x = 512x{\left( {1 - \frac{{15}}{k}} \right)^3}\\ \Rightarrow \frac{{343}}{{512}} = {\left( {\frac{7}{8}} \right)^3} = {\left( {1 - \frac{{15}}{k}} \right)^3}\\ \Rightarrow \left( {1 - \frac{{15}}{k}} \right) = \frac{7}{8} = \left( {1 - \frac{1}{8}} \right) \end{array} ∴ k = 120 Hence, the initial amount of wine in the container was 120 litres.

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