Subject

    Quantitative Aptitude

    Topic

    Simplification

    Find the value of ‘?’ in the given expression: 218%  of  320  of(114%  of  280  ÷(441−11)%  of  140)=?2\frac{1}{8}\% \;of\;320\;of\left( {1\frac{1}{4}\% \;of\;280\; \div \left( {\sqrt {441} - 11} \right)\% \;of\;140} \right) = ?

    ক)
    1
    খ)
    \(2\frac{7}{{10}}\)
    গ)
    \(1\frac{3}{{10}}\)
    ঘ)
    \(1\frac{7}{{10}}\)
    ঙ)
    None of these

    Explanation

    Follow BODMAS rule to solve this question, as per the order given below, Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, Step-2- Any mathematical 'Of' or 'Exponent' must be solved next, Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated. Given expression: 218%  of  320  of(114%  of  280  ÷(441−11)%  of  140)=?⇒8×2+18×100  of  320  of(1×4+14×100  of  280  ÷(21−11)100  of  140)=?⇒17800  of  320  of(72  ÷10100  of  140)=?⇒345  of(72  ÷14)=?⇒345  of(72×114)=?⇒345  of14  =?⇒?=1710=1710\begin{array}{l} 2\frac{1}{8}\% \;of\;320\;of\left( {1\frac{1}{4}\% \;of\;280\; \div \left( {\sqrt {441} - 11} \right)\% \;of\;140} \right) = ?\\ \Rightarrow \frac{{8 \times 2 + 1}}{{8 \times 100}}\;of\;320\;of\left( {\frac{{1 \times 4 + 1}}{{4 \times 100}}\;of\;280\; \div \frac{{\left( {21 - 11} \right)}}{{100}}\;of\;140} \right) = ?\\ \Rightarrow \frac{{17}}{{800}}\;of\;320\;of\left( {\frac{7}{2}\; \div \frac{{10}}{{100}}\;of\;140} \right) = ?\\ \Rightarrow \frac{{34}}{5}\;of\left( {\frac{7}{2}\; \div 14} \right) = ?\\ \Rightarrow \frac{{34}}{5}\;of\left( {\frac{7}{2} \times \frac{1}{{14}}} \right) = ?\\ \Rightarrow \frac{{34}}{5}\;of\frac{1}{4}\; = ?\\ \Rightarrow ? = \frac{{17}}{{10}} = 1\frac{7}{{10}} \end{array}

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