Subject

    Quantitative Aptitude

    Topic

    Miscellaneous

    An alloy contains copper and zinc in the ratio of 4:3 and another contains copper and tin in the ratio of 9:5. If equal weights of the two are melted together to form a new alloy, find the weight of tin per kg in the new alloy.

    ক)
    3/14 kg
    খ)
    5/13 kg
    গ)
    17/28 kg
    ঘ)
    5/28 kg
    ঙ)
    9/28 kg

    Explanation

    ∵ Equal weights of two alloys are melted together to form a new alloy, let the weights of both the alloys taken be x kg In the x kg of first alloy, weight of copper =44+3×x=4x7= \frac{4}{{4 + 3}} \times x = \frac{{4x}}{7} kg Weight of zinc in x kg of first alloy =x−4x7=3x7= x - \frac{{4x}}{7} = \frac{{3x}}{7} kg Similarly, in x kg of second alloy, weight of copper =99+5×x=9x14= \frac{9}{{9 + 5}} \times x = \frac{{9x}}{{14}} kg Weight of tin in x kg of second alloy =x−9x14=5x14= x - \frac{{9x}}{{14}} = \frac{{5x}}{{14}} kg When the two alloys are melted and fused together, the amount of tin in the total mixture will not change. Total weight of the mixture = x + x = 2x kg ∴ratio of weight of tin to total weight =5x142x=528= \frac{{\frac{{5x}}{{14}}}}{{2x}} = \frac{5}{{28}}

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