Subject

    Quantitative Aptitude

    Topic

    Age

    A woman is 30 times older than his son. 18 years later she will be thrice as old as her son. What is the woman’s present age in years?

    ক)
    30
    খ)
    35
    গ)
    36
    ঘ)
    40

    Explanation

    Let at present, Woman's age be x and her son's age be y Then, A/Q, x=30y ................................................. (1) 18 years later, Woman's age = x+18 her son's age= y+18 Now, A/Q, x+18=3*(y+18) or, x+18=3y+54 or, x-3y=54-18 or, x-3y= 36 or, 30y - 3y = 36 [From eq (1)] or, 27y = 36 or, y = 36/27 = 12/9 = 4/3 So, y= 4/3 Then, x= 30*4/3 = 40 years

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