Subject
Quantitative Aptitude
Topic
Miscellaneous
A vessel is full of mixture of spirit and water in which there is found to be 17% of spirit by measure. Ten litres are drawn off, and the vessel is filled up with water. The proportion of spirit is now found to be How much does the vessel hold ?
A vessel is full of mixture of spirit and water in which there is found to be 17% of spirit by measure. Ten litres are drawn off, and the vessel is filled up with water. The proportion of spirit is now found to be How much does the vessel hold ?
ক)
30 litresখ)
60 litresগ)
90 litresঘ)
120 litresঙ)
None of theseExplanation
Let the volume of the vessel be v. Given, 17 % of the vessel is filled with spirit. ∴ volume of spirit present = 17% of v ⇒ volume of spirit present = 0.17v Now, 10 liters are drawn off, ∴ total volume remaining = v – 10 In 10 liters volume of spirit present = 17% of 10 = 1.7 liters Thus, volume of spirit remaining = 0.17v – 1.7 As the container is filled with the water again ⇒ % of spirit present now = [(0.17v – 1.7) / (v)] × 100 % Given in question, % of spirit present in the new situation is 136/9 % ⇒ 136/9 = [(0.17v – 1.7) / (v )] × 100 ⇒ 136v = 153v – 1530 ⇒ 17v = 1530 ⇒ v = 90 litresRelated questions
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