Subject

    Quantitative Aptitude

    Topic

    Speed & Distance

    A train 75 metres long overtook a person (going in the same direction) who was walking at the rate of 6 km an hour, and passed him in 7127\frac{1}{2} seconds. Subsequently it overtook a second person (going in the same direction), and passed him in  6346\frac{3}{4} seconds. At what rate was the second person travelling?

    ক)
    2 km/hr
    খ)
    3 km/hr
    গ)
    5 km/hr
    ঘ)
    6 km/hr
    ঙ)
    None of these

    Explanation

    When the train passes the 1st person, Distance covered by the train = 0.075 km Speed (Relative) = x – 6 (where x is the the assumed speed of the train) Time = 7.5/3600  hrs Speed = Distance/Time ∴ x – 6 = 0.0757.53600\frac{{0.075}}{{\frac{{7.5}}{{3600}}}} ∴ x = 42 km/hr Thus the speed of the train is 42 km/hr Case 2: When the train passes the 2nd person Distance = 0.075 km Time = 6.75/3600 hrs Speed = 42 – y (Where y is assumed to be the speed of the 2nd person) Speed = Distance/Time ∴ 42 – y = 0.075/(6.75/3600) ∴ y = 2km/hr Thus the 2nd person was walking with the speed of 2km/hr

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