Subject
Quantitative Aptitude
Topic
Speed & Distance
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
ক)
48 km/hrখ)
54 km/hrগ)
66 km/hrঘ)
82 km/hrExplanation
Let the speed of the second train be x km/hr. Relative speed = (x + 50) km/hr = [ (x + 50) x 5/18] m/sec = [ (250 + 5x)/18] m/sec. Distance covered = (108 + 112) = 220 m. Therefore, 220/((250+5x)/18)= 6 => 250 + 5x = 660 => x = 82 km/hr.Related questions
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