A tin contains a mixture of coke and peps… | Answer

Subject

Quantitative Aptitude

Topic

Miscellaneous

A tin contains a mixture of coke and pepsi in the ratio of 7 : 3 and another tin contains the coke and pepsi in the ratio of 5 : 4. In what proportion should the solution of the two tins be mixed to achieve a perfect proportion of 2 : 1(inn which coke is 2 times of pepsi)?
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ক)

11 : 4

খ)

10 : 3

গ)

12 : 5

ঘ)

11 : 7

ঙ)

None of these

Explanation

According to the question, in, The mixture M 1 - Coke : pepsi = 7 : 3 The mixture M 2 - Coke : pepsi = 5 : 4 Proportion of coke in the mixture M 1 = 7/10, Proportion of coke in the mixture M 2 = 5/9, Proportion of the new mixture = 2/3 (required) According to the law of mixture-

Required\ ratio = \frac{{\frac{2}{3} - \frac{5}{9}}}{{\frac{7}{{10}} - \frac{2}{3}}} = \frac{{\frac{1}{9}}}{{\frac{1}{{30}}}} = \frac{{10}}{3} = 10:3

Hence, the required ratio is 10 : 3.

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A tin contains a mixture of coke and pepsi in the ratio of 7 : 3 and another tin contains the coke and pepsi in the ratio of 5 : 4. In what proportion should the solution of the two tins be mixed to achieve a perfect proportion of 2 : 1(inn which coke is 2 times of pepsi)?Reading

A tin contains a mixture of coke and pepsi in the ratio of 7 : 3 and another tin contains the coke and pepsi in the ratio of 5 : 4. In what proportion should the solution of the two tins be mixed to achieve a perfect proportion of 2 : 1(inn which coke is 2 times of pepsi)?

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A tin contains a mixture of coke and pepsi in the ratio of 7 : 3 and another tin contains the coke and pepsi in the ratio of 5 : 4. In what proportion should the solution of the two tins be mixed to achieve a perfect proportion of 2 : 1(inn which coke is 2 times of pepsi)?
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