Subject

    Quantitative Aptitude

    Topic

    Mensuration

    A solid cylinder has a total surface area of 231 cm2. It its curved surface area is two thirds of the total surface area, the volume of the cylinder is

    ক)
    269.5 cm2
    খ)
    385 cm2
    গ)
    308 cm2
    ঘ)
    363.4 cm2
    ঙ)
    364.4 cm2

    Explanation

    We know that, Total surface area of a closed cylinder = area of curved surface + area of circular top and bottom ∴ Total surface area of closed cylinder = 2πrh + 2πr 2 = 2πr(r+h) sq. units Where, r = radius of base of cylinder, h = height of cylinder According to the condition given in the question, Curved surface area = (2/3) ×Total surface area ∴2πrh  =23×2πr(r+h)\therefore 2\pi rh\; = \frac{2}{3} \times 2\pi r\left( {r + h} \right) ⇒ 3h = 2 × (r + h) ⇒ h = 2r Now, total surface area of a closed cylinder = 2πr(r+h) = 231 cm 2 ∴2πr(r+2r) = 231 6πr 2 = 231 ⇒r2=2316π=  494  cm2\Rightarrow {r^2} = \frac{{231}}{{6\pi }} = \;\frac{{49}}{4}\;c{m^2} ⇒ r = 7/2 = 3.5 cm ∴ Volume of a right circular cylinder = πr 2 h cubic units ⇒ Volume of the given cylinder = π r 2 × 2r = 2π r 3 ⇒ Volume of the given cylinder = π r 2 × 2r = 2π r 3 = 269.5 cm 3

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