Subject
Quantitative Aptitude
Topic
Probability
A room contains 3 red, 5 green and 4 blue chairs. Two chairs are picked and are put in the lawn. What is the probability that none of the chairs picked is blue?
A room contains 3 red, 5 green and 4 blue chairs. Two chairs are picked and are put in the lawn. What is the probability that none of the chairs picked is blue?
ক)
14/33খ)
9/22গ)
1/6ঘ)
1/3ঙ)
None of theseExplanation
⇒ Total number of chairs = (3 + 5 + 4) = 12. Let S be the sample space. Then, n(s)= Number of ways of picking 2 chairs out of 12 Let n(E) = number of events of selecting 2 chairs for selecting no blue chairs. Therefore required probability = 28/66 = 14/33Related questions
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