Subject
Quantitative Aptitude
Topic
Speed & Distance
A man can walk uphill at the rate of 2(1/2)km/hr and downhill at the rate of 3(1/4)km/hr. If the total time required to walk a certain distance up the hill and return to the starting point was 4 hr 36 min, then what was the distance walked up the hill by the man? ( একজন লোক 2(1/2)km/hr বেগে পাহাড়ে উঠতে পারে এবং 3(1/4)km/hr বেগে পাহাড় হতে নেমে আসতে পারে । এভাবে পাহাড়ে উঠে আবার পূর্বের স্থানে নিয়ে আসতে যদি মোট 4 hr 36 min সময় লাগে তাহলে ঐ লোক পাহাড়ে কত দূরত্ব হেঁটেছিল?)
A man can walk uphill at the rate of 2(1/2)km/hr and downhill at the rate of 3(1/4)km/hr. If the total time required to walk a certain distance up the hill and return to the starting point was 4 hr 36 min, then what was the distance walked up the hill by the man? ( একজন লোক 2(1/2)km/hr বেগে পাহাড়ে উঠতে পারে এবং 3(1/4)km/hr বেগে পাহাড় হতে নেমে আসতে পারে । এভাবে পাহাড়ে উঠে আবার পূর্বের স্থানে নিয়ে আসতে যদি মোট 4 hr 36 min সময় লাগে তাহলে ঐ লোক পাহাড়ে কত দূরত্ব হেঁটেছিল?)
ক)
4 kmখ)
4(1/2)kmগ)
5(1/2)kmঘ)
6(1/2)kmExplanation
মনে করি, সে দূরত্ব উঠেছিল = x km 2 (1/2) = 5/2 , 3 (1/4) = 13/4 জানা আছে, বেগ = বেগ=(দূরত্ব/সময়) বা, সময়= (দূরত্ব/বেগ) x km উঠতে সময় লাগে ={ x km/(5/2) km/hr} = (2x/5) hr এবং x km নামাতে সময় লাগে = {x km/(13/4) km/hr} = (4x/13) hr দেওয়া আছে, মোট সময় = 4 hr and 36 min = 4 hr and (36/60) hr ={4+(36/60)} hr = {4+(6/10)} hr = (46/10) hr শর্তমতে, 2x/5 + 4x/13 = (46/10) বা {(26x+20x)/(5×13)} = (46/10) বা, {46x(5×13)} = (46/10) ∴ {(46×5×13)/(10×46)} = (13/2) = 6 (1/2) kmRelated questions
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