A group of kids decided to compete by thr… | Answer

Subject

Quantitative Aptitude

Topic

Mensuration

A group of kids decided to compete by throwing maximum number of stones in a tank which is 80 m long and 50 m. broad. If 250 stones were thrown by them and the average displacement of 1 stone is 4 cub. m, what was the rise in the water level?
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ক)

50 cm

খ)

75 cm

গ)

90 cm

ঘ)

25 cm

ঙ)

None of these

Explanation

Displacement of water by a single kid = 4 cub. m Then, Displacement by 250 stones = number of kids × Displacement by one stone Displacement by 250 Stones = 250 × 4 = 1000 cub. m Since the area of tank = length of the tank × breadth of the tank = 80m × 50m = 4000 sq m. Rise in water level = volume of water displaced by 250 kids/area of the tank ⇒ Rise in water level = 1000/4000 = 0.25 m Since 1 m = 100 cm So, Rise in water level = 0.25 × 100 = 25 cm

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A group of kids decided to compete by throwing maximum number of stones in a tank which is 80 m long and 50 m. broad. If 250 stones were thrown by them and the average displacement of 1 stone is 4 cub. m, what was the rise in the water level?Reading

A group of kids decided to compete by throwing maximum number of stones in a tank which is 80 m long and 50 m. broad. If 250 stones were thrown by them and the average displacement of 1 stone is 4 cub. m, what was the rise in the water level?

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A group of kids decided to compete by throwing maximum number of stones in a tank which is 80 m long and 50 m. broad. If 250 stones were thrown by them and the average displacement of 1 stone is 4 cub. m, what was the rise in the water level?
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