Subject
Quantitative Aptitude
Topic
Simplification
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
ক)
30 birdsখ)
60 birdsগ)
72 birdsঘ)
90 birdsExplanation
Let the total number of shots be x. Then, Shots fired by A = (5/8)x Shots fired by B = (3/8)x Killing shots by A = 1/3 of (5/8)x = (5/24)x Shots missed by B = 1/2 of (3/8)x = (3/16)x So, 3x/16 = 27 or x =(27 x 16)/3 = 144. Birds killed by A = 5x/24 = (5/24)/144 = 30.Related questions
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