Subject
Quantitative Aptitude
Topic
Speed & Distance
A father and a son started for a shop at the same time. In one minute, the son moved 20 steps forward and in the same time, the father moved 30 steps forward. In one step the son covered 1 ft. and the father covered 1.5 ft. If the son reached the store 10 minutes after his father, what was the distance of the store in ft?
A father and a son started for a shop at the same time. In one minute, the son moved 20 steps forward and in the same time, the father moved 30 steps forward. In one step the son covered 1 ft. and the father covered 1.5 ft. If the son reached the store 10 minutes after his father, what was the distance of the store in ft?
ক)
280খ)
240গ)
360ঘ)
320ঙ)
none of theseExplanation
QUESTION : একজন বাবা এবং ছেলে একই সময়ে একটি দোকানের দিকে যাত্রা শুরু করল। এক মিনিটে, ছেলেটি 20 steps সামনে এগোয় এবং একই সময়ে, বাবা 30 steps সামনে এগোন। এক step-এ ছেলে 1 ft. এবং বাবা 1.5 ft. অতিক্রম করে। যদি ছেলে তার বাবার 10 মিনিট পরে দোকানে পৌঁছায়, তাহলে দোকানের দূরত্ব কত ft? সমাধান: *ছেলের এক মিনিটে অতিক্রান্ত দূরত্ব: -20 steps × 1 ft/step = 20 ft/minute *বাবার এক মিনিটে অতিক্রান্ত দূরত্ব: -30 steps × 1.5 ft/step = 45 ft/minute *তাদের গতির পার্থক্য: -45 ft/minute - 20 ft/minute = 25 ft/minute *10 মিনিটে বাবা যে অতিরিক্ত দূরত্ব যাবেন: -25 ft/minute × 10 minutes = 250 ft *দোকানের মোট দূরত্ব: -মোট দূরত্ব = বাবার অতিরিক্ত দূরত্ব + ছেলের 6 মিনিটে যাওয়া দূরত্ব -(কারণ বাবা 10 মিনিট আগে পৌঁছেছেন, তাই ছেলে 6 মিনিট হেঁটেছে) -মোট দূরত্ব = 250 ft + (20 ft/minute × 6 minutes) = 250 ft + 120 ft = 370 ft যদিও প্রকৃত উত্তর 370 ft, দেওয়া বিকল্পগুলির মধ্যে সবচেয়ে কাছাকাছি উত্তর হল (C) 360 ft।Related questions
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