Subject

    Quantitative Aptitude

    Topic

    Percentage

    A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ?

    ক)
    160
    খ)
    120
    গ)
    140
    ঘ)
    180

    Explanation

    Given total number of cows = k Now, 1st son share = k/2 2nd son share = k/4 3rd son share = k/5 4th son share = 9 (k) + (k/4) + (k/5) + 9 = k => k - (19k/20) = 9 => (20k-19k)/20 = 9 => k = 180.

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