Subject
Bank Exam
Topic
Southeast Bank Ltd. - Probationary Officer - 2016
A cyclist leaves home at 10.00 hours to cycle to school 7 km a way. He cycles at 10 km/h until he has a puncture, then he has to push his bicycle the rest of the way at 3 km/h. He arrives at school at 11.10 hours. How far he walked ?
A cyclist leaves home at 10.00 hours to cycle to school 7 km a way. He cycles at 10 km/h until he has a puncture, then he has to push his bicycle the rest of the way at 3 km/h. He arrives at school at 11.10 hours. How far he walked ?
ক)
2 km.খ)
3 km.গ)
4 km.ঘ)
1 km.Explanation
Solution: একজন সাইক্লিস্ট/ সাইকেল আরোহী 10.00 টার সময় বাড়ি থেকে বের হয়ে 7 km দূরে স্কুলে যায় । সাইকেলের চাকা লিক হবার পূর্ব পর্যন্ত সে ঘন্টায় 10 km যায়, বাকী রাস্তা সে সাইকেল ঠেলে/ধাক্কাতে ধাক্কাতে ঘন্টায় 3 km যায় । সে স্কুলে 11.10 এ পৌছায় । সে কত দূরে হেঁটে ছিলো ? মনে করি, সে x কিমি হেঁটে যায় । তাহলে, সে সাইকেল চালিয়ে যায় = (7 - x) km স্কুলে পৌছাতে যে সময় নেয় (11.10 - 10.00) = 1 ঘন্টা 10 মিনিট = ঘন্টা প্রশ্নমতে, [ দূরত্ব/বেগ = মোট সময় ] => => 10x + 21 - 3x = => 7x + 21 = 35 => 7x = 35 - 21 => 7x = 14 x = 2 অর্থাৎ সে 2 km হেঁটে যায় ।Related questions
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